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2a^2=14400
We move all terms to the left:
2a^2-(14400)=0
a = 2; b = 0; c = -14400;
Δ = b2-4ac
Δ = 02-4·2·(-14400)
Δ = 115200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{115200}=\sqrt{57600*2}=\sqrt{57600}*\sqrt{2}=240\sqrt{2}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-240\sqrt{2}}{2*2}=\frac{0-240\sqrt{2}}{4} =-\frac{240\sqrt{2}}{4} =-60\sqrt{2} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+240\sqrt{2}}{2*2}=\frac{0+240\sqrt{2}}{4} =\frac{240\sqrt{2}}{4} =60\sqrt{2} $
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